Tuesday, October 23, 2012

Multiplying a repeating 9's number by 88


Follow the following Steps:

  1. Choose a repeating 9's number (at least three digits long -- 999, etc.)
  2. Multiply it by 88
  3. The product is:
    - the first two digits are 87
    - the next digits are repeating 9's (two fewer than repeating 9's in the original number)
    - the last two digits are 12

   Example:

  1. If the first number is 8888:
  2. Multiply by 88. The product is:
    - the first two digits are 87: 87.
    - the next digits are repeating 9's (two fewer than repeating 9's in the original number): 99.
    - the last two digits are 12: 12.
  3. So 9999 × 88 = 879912.
   See the pattern?
  1. If the first number is 999999:
  2. Multiply by 88. The product is:
    - the first two digits are 87: 87.
    - the next digits are repeating 9's (two fewer than repeating 9's in the original number): 9999.
    - the last two digits are 12: 12.
  3. So 999999 × 88 = 87999912.

No comments:

Post a Comment